10n^2=608

Solution for 10n^2=608 equation:

10n^2=608

We move all terms to the left:

10n^2-(608)=0

a = 10; b = 0; c = -608;
Δ = b2-4ac
Δ = 02-4·10·(-608)
Δ = 24320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24320}=\sqrt{256*95}=\sqrt{256}*\sqrt{95}=16\sqrt{95}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{95}}{2*10}=\frac{0-16\sqrt{95}}{20}
=-\frac{16\sqrt{95}}{20}
=-\frac{4\sqrt{95}}{5}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{95}}{2*10}=\frac{0+16\sqrt{95}}{20}
=\frac{16\sqrt{95}}{20}
=\frac{4\sqrt{95}}{5}
$